Hensel’s Lemma
If f(m) ≡ 0 (mod p^s) and p does not divide f’(m)
then there exists a unique r such that
f m + rp^s) ≡ 0 (mod p^(s+1)).
That Hensel. He’s sooo hot right now.
Studying number theory. FUUUUUUU….
If f(m) ≡ 0 (mod p^s) and p does not divide f’(m)
then there exists a unique r such that
f m + rp^s) ≡ 0 (mod p^(s+1)).
That Hensel. He’s sooo hot right now.
Studying number theory. FUUUUUUU….
